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Why can an interface supertype call methods that belong to Object class? |
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The members of an interface are:
1) Those members declared in the interface. 2) Those members inherited from direct superinterfaces. 3) If an interface has no direct superinterfaces, then the interface implicitly declares a public abstract member method m with signature s, return type r, and throws clause t corresponding to each public instance method m with signature s, return type r, and throws clause t declared in Object, unless a method with the same signature, same return type, and a compatible throws clause is explicitly declared by the interface. It is a compile-time error if the interface explicitly declares such a method m in the case where m is declared to be final in Object. |
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